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2x^2+10=-44-x^2
We move all terms to the left:
2x^2+10-(-44-x^2)=0
We get rid of parentheses
2x^2+x^2+44+10=0
We add all the numbers together, and all the variables
3x^2+54=0
a = 3; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·3·54
Δ = -648
Delta is less than zero, so there is no solution for the equation
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